Answer:
1.37 * 10^ 27 watts
Explanation:
The power radiated by a body with surface temperature T and surface area A is given by
[tex]P=\sigma AT^4[/tex]where σ = 5.67 x 10^-8 watt / m^2 K^4.
Now in our case
A = 6.89 x 10^18 m^2 and T = 7701.
Therefore,
[tex]P=5.67\times10^{-8}\times6.89\cdot10^{18}\times7701^4[/tex]which we evaluate to get
[tex]\boxed{P=1.37\times10^{27}W.}[/tex]Hence, the power radiated by the star is 1.37 x 10^27 watts.
