Respuesta :
if the ball's diameter is 10, the radius is half that, or 5 then,
[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\quad \begin{cases} r=radius\\ -----\\ r=5 \end{cases}\implies V=\cfrac{4\pi \cdot 5^3}{3}[/tex]
[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\quad \begin{cases} r=radius\\ -----\\ r=5 \end{cases}\implies V=\cfrac{4\pi \cdot 5^3}{3}[/tex]