EXPLANATION:
1.We must first locate the intersection points for the graph
[tex]\begin{gathered} h(X)=(\frac{1}{2}x-2)^2 \\ (\frac{x}{2}-2)^2 \\ inter\sec t\text{ in x : }(4,0)\text{ } \\ \text{ intersect in y: }(0,4) \end{gathered}[/tex]
By giving points to the equation we can have the graph of an upward curve.
The graph is the following:
