SOLUTION
8 is not an outlier, the outlier is 1.
The mean is
[tex]\frac{1+6+6+6+8}{5}=\frac{27}{5}=5.4[/tex]Hence, the mean is 5.4 not 4.5.
The range is,
[tex]8-1=7[/tex]Hence, the range is 7 not 6.
Therefore, the answer is the data is concentrated around 6 and 1 is an outlier.