Respuesta :
Answer : The number of moles of air present is, 0.055 mole
Solution :
Using ideal gas equation :
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 750 torr = 0.98 atm (1 atm = 760 torr)
V = volume of the gas = 1.35 L
T = temperature of the gas = [tex]17^oC=17+273=290K[/tex]
R = gas constant = 0.0821 Latm/moleK
n = number of moles of air = ?
Now put all the given values in this formula, we get the number of moles of air present.
[tex](0.98atm)\times (1.35L)=n\times (0.0821Latm/moleK)\times (290K)[/tex]
[tex]n=0.055mole[/tex]
Therefore, the number of moles of air present is, 0.055 mole
