Answer:
5 and 6.
Explanation:
First, we consider the perfect squares less than and greater than 29.
[tex]25<29<36[/tex]Thus:
[tex]\begin{gathered} \sqrt[]{25}<\sqrt[]{29}<\sqrt[]{36} \\ =5<\sqrt[]{29}<6 \end{gathered}[/tex]Therefore, the square root of 29 is between the integers 5 and 6.
