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Two pools are being filled with water. To start, the first pool contains 1210 liters of water and the second pool is empty. Water is being added to the first pool ata rate of 15.25 liters per minute. Water is being added to the second pool at a rate of 45.5 liters per minute.After how many minutes will the two pools have the sameamount of water?minutesHow much water will be in each pool when they have thesame amount?liters

Respuesta :

Given Two pools are being filled with water.

First pool: Contain 1210 liters, rate of adding water 15.25 liters per minute

Second pool: Empty, rate of adding water 45.5 liters per minute

Let the number of minutes needed to have the same amount of water = t

So,

[tex]1210+15.25t=45.5t[/tex]

Solve for t:

[tex]\begin{gathered} 1210=45.5t-15.25t \\ 1210=30.25t \\ t=\frac{1210}{30.25}=40\min \text{.} \end{gathered}[/tex]

So, the answer will be after 40 minutes both pools have the same amount of water

The amount of water at each pool = 45.5 x 40 = 1,820 liters