First,
we have 3 compounds in the solution:
-Chloroform
-Heptane
-Acetyl bromide
Mass % = (Mass solute / Mass of solution) x 100
Mass of solution = 30.8 g of Chloroform + 32.4 g of Heptane + 63.8 g of Acetyl bromide = 127 g
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- Mass % Chloroform = (30.8 g / 127 g ) x 100 = 24.2 % (w/w)
- Mass % Heptane = (32.4 g / 127 g) x 100 = 25.5 % (w/w)
- Mass % Acetyl bromide = (63.8 g / 127 g) = 50.2 % (w/w)
