Respuesta :
Answer:
The correct option is A) zero percent
Explanation:
Hemophilia can be described as an X-linked recessive disorder in which the blood of a person is not able to clot properly. As it is a recessive disorder, both the alleles should be recessive for the disorder to occur. In males, as only one X chromosome is present hence, only one allele would be enough to cause the disorder in males. Whereas for females, both the X chromosomes will have to carry the recessive type alleles for the disorder to occur.
Hemophilia is an X-linked recessive disease. The probability that a female child would suffer from hemophilia is 0% if at least one of the parental genotypes carries the dominant allele, X⁺.
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We know that Hemophilia is an X-linked recessive disorder.
We will say that the X chromosome with the recessive allele is X⁻, while the X chromosome with the dominant allele is X⁺.
Since I do not have the genotypes of Charles and Marie, I will provide different pottential scenarios.
Scenario 1)
- Charles : X⁻Y
- Marie : X⁺X⁺
Parentals) X⁺X⁺ x X⁻Y
Gametes) X⁺ X⁺ X⁻ Y
Punnett square) X⁺ X⁺
X⁻ X⁺X⁻ X⁺X⁻
Y X⁺Y X⁺Y
F1) 0% of the progeny will suffer from hemophilia
The probability that a female child of Charles and Marie would suffer from hemophilia is 0%.
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Scenario 2)
- Charles : X⁻Y
- Marie : X⁺X⁻
Parentals) X⁺X⁻ x X⁻Y
Gametes) X⁺ X⁻ X⁻ Y
Punnett square) X⁺ X⁻
X⁻ X⁺X⁻ X⁻X⁻
Y X⁺Y X⁻Y
F1) 50% of the progeny will suffer from hemophilia
The probability that a female child of Charles and Marie would suffer from hemophilia is 50% (1/2) considering only females, and 25% (1/4) considering the whole progeny.
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Scenario 3)
- Charles : X⁻Y
- Marie : X⁻X⁻
Parentals) X⁻X⁻ x X⁻Y
Gametes) X⁻ X⁻ X⁻ Y
Punnett square) X⁻ X⁻
X⁻ X⁻X⁻ X⁻X⁻
Y X⁻Y X⁻Y
F1) 100% of the progeny will suffer from hemophilia
The probability that a female child of Charles and Marie would suffer from hemophilia is 100%
****************************
Scenario 4)
- Charles : X⁺Y
- Marie : X⁻X⁻
Parentals) X⁻X⁻ x X⁺Y
Gametes) X⁻ X⁻ X⁺ Y
Punnett square) X⁻ X⁻
X⁺ X⁺X⁻ X⁺X⁻
Y X⁻Y X⁻Y
F1) 50% of the progeny will suffer from hemophilia
The probability that a female child of Charles and Marie would suffer from hemophilia is 0%
****************************
Scenario 5)
- Charles : X⁺Y
- Marie : X⁺X⁻
Parentals) X⁺X⁻ x X⁺Y
Gametes) X⁺ X⁻ X⁺ Y
Punnett square) X⁺ X⁻
X⁺ X⁺X⁺ X⁺X⁻
Y X⁺Y X⁻Y
F1) 25% of the progeny will suffer from hemophilia
The probability that a female child of Charles and Marie would suffer from hemophilia is 0%.
****************************
Scenario 6)
- Charles : X⁺Y
- Marie : X⁺X⁺
Parentals) X⁺X⁺ x X⁺Y
Gametes) X⁺ X⁺ X⁺ Y
Punnett square) X⁺ X⁺
X⁺ X⁺X⁺ X⁺X⁺
Y X⁺Y X⁺Y
F1) 0% of the progeny will suffer from hemophilia
The probability that a female child of Charles and Marie would suffer from hemophilia is 0%.
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You can learn more about hemophilia at
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