From the diagram we have that H is -30 km in the x-direction and 20 km in the y-direction.
We also have that F is -30 km in the x-direction and -30 km in the y-direction.
Then the resultant will be -60 km in the x-direction and -10 km in the y-direction.
Then the table woluld be:
The magnitude of the resultant is:
[tex]\begin{gathered} R=\sqrt[]{(-60)^2+(-10)^2} \\ R=60.83 \end{gathered}[/tex]
Therefore its resultant is 60.83 km (using two decimals).
The angle is given by:
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{10}{60}) \\ \theta=9.46 \end{gathered}[/tex]
Now, this is the angle in the third quadrant. Therefore the angle measuere from the x-axis CCW is 189.46°
