Answer:
Explanation:
As momentum is conserved, and car 1 lost 100 - 40 = 60 kg•m/s of momentum, car 2 must have gained 60 kg•m/s during the collision.
The velocity of car 1 (and therefore car 2) after the collision is
v = p/m = 40/14.5 = 2.7586... m/s
the momentum equation for car2 is
m₂(u) + Δp = m₂(v)
u = (m₂(v) - Δp) / m₂
u = v - Δp / m₂
u = 2.7586 - 60 / 45.0
u = 1.4252...
u = 1.43 m/s
