Answer
The grams of calcium produced will be 44.44 grams
Explanation
The equation for the reaction is:
3CaCl₂ + 2Al → 2AlCl₃ + 3Ca
From the equation; 2 mol Al = 3 mol Ca
1 mole of Al = 27 g/mol
1 mole of Ca = 40 g/mol
Therefore, the mass of Ca produced when 20 g of Al react is:
[tex]\begin{gathered} 2mol\times27g\text{/}mol\text{ }Al=3mol\times40g\text{/}mol\text{ }Ca \\ \\ 20g\text{ }Al=x \\ \\ x=\frac{20g\text{ }Al}{2mol\times27g\text{/}mol\text{ }Al}\times3mol\times40g\text{/}mol\text{ }Ca \\ \\ x=\frac{20g}{54g}\times120g\text{ }Ca \\ \\ x=44.44\text{ }grams\text{ }Ca \end{gathered}[/tex]Thus, the grams of calcium produced will be 44.44 grams
