Answer:
power emitted is 1.75 W
Explanation:
given data
length l = 5 cm = 5 ×[tex]10^{-2}[/tex] m
diameter d = 0.074 cm = 74 ×[tex]10^{-5}[/tex] m
total filament emissivity = 0.300
temperature = 3068 K
to find out
power emitted
solution
we find first area that is π×d×L
area = π×d×L
area = π×74 ×[tex]10^{-5}[/tex]×5 ×[tex]10^{-2}[/tex]
area = 1162.3892 ×[tex]10^{-5}[/tex] m²
so here power emitted is express as
power emitted = E × σ × area × (temperature)^4
put here all value
power emitted = 0.300× 5.67 × 1162.3892 ×[tex]10^{-5}[/tex] × (3068)^4
power emitted = 1.75 W
