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If both cars in Exercise 62 are on one side of the plane and if the angle of depression to one car is 38∘ and that to the other car is 52∘, how far apart are the cars?

If both cars in Exercise 62 are on one side of the plane and if the angle of depression to one car is 38 and that to the other car is 52 how far apart are the c class=

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raphealnwobi

The two cars lying on one side of the plane are 50 meters apart.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

let us assume that the height is 100 m. Let d represent the horizontal distance. For depression of 38°, Ф = 90 - 38 = 52°, hence:

tan(52°) = d / 100

d = 128 m

For depression of 52°, Ф = 90 - 52 = 38°, hence:

tan(38°) = d / 100

d = 78 m

Distance apart = 128 - 78 = 50 m.

The two cars lying on one side of the plane are 50 meters apart.

Find out more on equation at: https://brainly.com/question/2972832

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