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A 6.0-kilogram block slides along a horizontal surface. If μk = 0.20 for the block and surface, at what rate is the friction force doing work on the block at an instant when its speed is 4.0 m/s?

Respuesta :

Answer:

Power = 47.0 Watt

Explanation:

As we know that friction force is given by

[tex]F_f = \mu mg[/tex]

now we have

[tex]\mu = 0.20[/tex]

m = 6.0 kg

now we have

[tex]F_f = 0.20(6.0)(9.80) = 11.76 N[/tex]

now since we need to find the rate of work done by friction force

so we can say rate of work done is power due to friction force

so it is given as

[tex]P = F_f (v)[/tex]

[tex]P = 11.76 (4.0)[/tex]

[tex]P = 47.0 Watt[/tex]

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