Answer:
The pool cannot be neutralized with only vinegar.
Explanation:
The pool's [OH] concentration is 1.0x101mol/L. You must determine the volume of the pool in order to determine how many moles of OH there are in the solution:
r2h = V(pool)
Where h is the depth of the pool, which is equal to 10 meters, and r is the radius,
V(pool) = π (6m)
V(pool) = 2*10 = 1131 m3.
As 1m³ = 1000L
The pool holds 1131m3 x (1000L / 1m3) = 1131000L.
And the OH moles are:
The pool has 131100 moles of OH, or 1.0x101mol per liter times 1131000 liters.
The following is how H+ neutralizes OH:
OH⁻ + H⁺ → H₂O
In order to neutralize the pool, 131100 moles of H+ must be added.
H+ levels in vinegar with a pH of 2 are as follows:
[H+] = -log pH
2 = -log [H⁺]
1x10⁻²M = [H⁺]
Only 4x102 moles of [H+] make up 4L. As necessary, 131100 moles of H⁺:
Source: https://brainly.com/question/17124531