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A rare species of insect was discovered in the rain forest. In order to protect the species,
environmentalists declare the insect endangered and transplant the insects into a protected area.
The population of the insect t months after being transplanted is given by P(t).
P(t) =
60(1+0.4)
0.01t+3
a. How many insects were discovered? In other words, what was the population when t = 0?
b. What will the population be after 5 years? Round to the nearest whole insect.

Respuesta :

Using the given function, it is found that:

a) 20 insects were discovered.

b) The population after 5 years will be of 417 insects.

What is the function for the number of insects after t months?

As stated in the exercise, it is given by:

[tex]P(t) = \frac{60(1 + 0.4t)}{0.01t + 3}[/tex]

Item a:

[tex]P(0) = \frac{60[1 + 0.4(0)]}{0.01(0) + 3} = \frac{60}{3} = 20[/tex]

20 insects were discovered.

Item b:

5 years = 60 months, hence:

[tex]P(60) = \frac{60[1 + 0.4(60)]}{0.01(60) + 3} \approx 417[/tex]

The population after 5 years will be of 417 insects.

More can be learned about functions at https://brainly.com/question/25537936

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