Respuesta :
The pressure of the hydrogen gas formed is given by its partial pressure at
the given temperature.
The pressure of the hydrogen gas formed is approximately 717.38 mmHg.
Reasons:
The pressure of the hydrogen gas formed is given by the difference
between the vapor pressure of the gas collected and the vapor pressure of
water.
The vapor pressure of water at 24.0 °C is given by the Clausius-Clapeyron
Equation as follows;
[tex]ln \left(\dfrac{P_2}{P_1} \right) = \dfrac{\Delta H_{vap}}{R} \cdot \left(\dfrac{1}{T_1} - \dfrac{1}{T_2} \right)[/tex]
Where;
P₁ = The partial pressure at temperature, T₁
P₂ = The pressure at temperature, T₂
We get;
[tex]ln \left(\dfrac{P_2}{23.8 \ mmHg} \right) = \dfrac{44,000 \ J/mol}{8.3145 \ J/(mol \cdot K)} \cdot \left(\dfrac{1}{298 \ K} - \dfrac{1}{297.15 \ K} \right)[/tex]
The pressure of water at 24.0 °C, P₂ ≈ 22.62 mmHg
The vapor pressure of water at 24.0°C is 22.62 mmHg
Therefore;
The pressure of the hydrogen gas formed ≈ 740.0 mmHg - 22.62 mmHg = 717.38 mmHg
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