Answer:
To find the area of the triangle shown in the picture, we need to find the height and the base.
The length of the height should be:
cos45° = BC/AB
=> BC = AB · cos45° = 24 · cos45° = 12√2 (ft)
From the information provided, we can calculate ∠CAB which is 45°, therefore ΔABC is an isosceles triangle, meaning that BC = AC = 12√2 (ft)
The area of the figure is:
A = bh/2 = (12√2)²/2 = 144 (ft²)
