Given the following two reactions at 298 K and 1 atm, which of the statements is true?
1. N2 (g) + O2 (g) ----> 2NO (g) ΔH1
2. 1/2 N2 (g) + 1/2 O2 (g) ---> NO (g) ΔH2

a. ΔH1 = ΔH2
b. ΔH1 = 1/2 ΔH2
c. 2ΔH1 = ΔH2
d. ΔH1 = 2ΔH2
e. none are true

Respuesta :

The statement that is true among the given statements is ΔH1 = 2ΔH2. The correct option is d. ΔH1 = 2ΔH2

From the question,

We are to determine which of the given statements is true.

From the given reactions,

We have

1. N2 (g) + O2 (g) ----> 2NO (g) ΔH1

and  

2. 1/2 N2 (g) + 1/2 O2 (g) ---> NO (g) ΔH2

ΔH1 is the enthalpy change for reaction 1

and

ΔH2 is the enthalpy change for reaction 2

Enthalpy is an extensive property. The enthalpy change for a given reaction depends on the stoichiometry of the reaction.

From the given equations,

We can observe that the stoichiometry of reaction 1 is twice that of reaction 2.

Therefore, the enthalpy of reaction 1 will also be twice the enthalpy of reaction 2

That is,

ΔH1 = 2ΔH2

Hence, the statement that is true among the given statements is ΔH1 = 2ΔH2. The correct option is d. ΔH1 = 2ΔH2

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