A 2500kg automobile develops 30kW of power to drive with a constant velocity of 90km/h on a level ground. What power must it develop to drive up a 15 degree hill with the same velocity.

Respuesta :

Answer:

the power developed by the automobile is 7,764.57 W.

Explanation:

Given;

mass of the automobile, m = 2500 kg

initial power developed by the automobile, P₁ = 30 kW = 30,000 W

initial speed of the automobile, v₁ = 90 km/h = 25 m/s

inclination of the hill, θ = 15⁰

second speed of the automobile, v₂ = v₁Sinθ

The power developed by the automobile is calculated as;

P = Fv

[tex]F = \frac{P_1}{V_1} = \frac{P_2}{V_2} \\\\P_2 = \frac{P_1V_2}{V_1} \\\\P_2 = \frac{30,000 \ W \ \times 25Sin(15^0)}{25} \\\\P_2 = 30,000 \ \times sin(15^0)\\\\P_2 = 7,764.57 \ W\\\\[/tex]

Therefore, the power developed by the automobile is 7,764.57 W.