Answer:
-2
Step-by-step explanation:
Since the roots are known and the function is a quadratic function, we can write down the function:
y = (x+3)(x-2/3) since when the roots are plugged in, the function gives 0.
Standard form means that the function has to be expanded:
y = (x+3)(x-2/3) = [tex]x^{2}+3x - 2x/3 - 3*2/3[/tex]
y = [tex]x^{2}+ 7x/3 - 2[/tex]
The constant term is -2.
