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A particle moves along a straight line with equation of motion s = t^{5} - 2 t^{4} Find the value of t (other than 0 ) at which the acceleration is equal to zero.

Respuesta :

t^4(t-2)
roots t=2 , t=2
delta=0
derivation d/dt(t^5-2t^4)=t^3 (5t-8)
local maximin =max(t^5-2t^4)=0 at t=0
so by olving it we get 2.133 naswer

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