Answer:
The angle is [tex]\theta = 30^o[/tex]
Explanation:
From the question we are told that
The length of the wire is [tex]l = 0.60 \ m[/tex]
The current is [tex]I = 2.0 \ A[/tex]
The magnetic field strength is [tex]B = 0.30 \ T[/tex]
The magnitude of the magnetic force is [tex]F _b = 0.18 \ N[/tex]
Generally the magnetic force exerted on the wire is mathematically represented as
[tex]F_b = I * l * B * sin \theta[/tex]
Making [tex]\theta[/tex] the subject
[tex]\theta =sin^{-1} [ \frac{ F_b }{I * l * B } ][/tex]
substituting values
[tex]\theta =sin^{-1} [ \frac{ 0.18 }{ 2.0 * 0.6 * 0.3 } ][/tex]
[tex]\theta = 30^o[/tex]
