Answer:
3.26×10⁵m³
Explanation:
Given data:
Initial volume = 3.5×10⁵ m³
Initial temperature = 27 °C (27+273= 300 K)
Initial pressure = 101 Kpa
Final volume = ?
Final temperature = -10°C (-10+273 = 263 K)
Final pressure = 95 Kpa
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 101 Kpa × 3.5×10⁵ m³× 263 K / 300 K × 95 Kpa
V₂ = 92970.5 ×10⁵kpa. m³. K / 28500 K.Kpa
V₂ = 3.26×10⁵m³
