Answer:
0.15866 is the probability of the average fracture strength of selected 100 pieces of glasses that of exceed 14.3.
Step-by-step explanation:
Given that, the strength of a tempered(x) a glass has average 14.1 and has standard deviation 2.
[tex]\mu_x=14.1[/tex] , [tex]\sigma_x=2[/tex]
n=number of selected pieces= 100.
The probability that the average fracture strength of 100 pieces of this glass exceed 14.3 is
[tex]P(\overline X>14.3)=P(\frac{\overline X-\mu_x}{2/\sqrt n}>\frac{14.3-14.1}{2/\sqrt{100}})[/tex]
[tex]=P(\overline X>1)[/tex]
[tex]=1-P(\overline X\leq 1)[/tex]
= 1 - 0.84134
=0.15866.
