Answer: [tex]\$0.15[/tex]
Step-by-step explanation:
Given
Six apples and one pear cost [tex]\$1.07[/tex]
Also, three apples and six pears costs [tex]\$1.47[/tex]
Suppose [tex]x[/tex] and [tex]y[/tex] be the price of apple and pear. So, we can write the cost as
[tex]\Rightarrow 6x+y=1.07\quad \ldots(i)\\\Rightarrow 3x+6y=1.47\quad \ldots(ii)\\\text{solve (i) and (ii) we get}[/tex]
[tex]x=0.15,\ y=0.17[/tex]
The cost of an apple is [tex]\$0.15[/tex]
