The final position of the car is 385 m.
Explanation:
We know the formula :
s = [tex]ut +[/tex] [tex]\frac{1}{2} at^{2}[/tex]
where,
s = distance
u = initial velocity = 5.1 m/s
t = time taken = 14 sec
a = acceleration = 3.2 m/[tex]s^{2}[/tex]
Solving:
s = 5.1* 14 + [tex]\frac{1}{2}[/tex] * 3.2 * [tex]14^{2}[/tex]
∴ s = 385 m
Hence the final position of the car is 385 m.
