In 2011 a​ country's federal receipts​ (money taken​ in) totaled ​$2.31 trillion. In​ 2013, total federal receipts were ​$2.83 trillion. Assume that the growth of federal​ receipts, F, can be modeled by an exponential function and use 2011 as the base year ​(tequals​0).
​a) Find the growth rate k to six decimal​ places, and write the exponential function​ F(t), for total receipts in trillions of dollars.
​b) Estimate total federal receipts in 2015. ​
c) When will total federal receipts be ​$10 ​trillion?

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Answer:

Step-by-step explanation:

An exponential equation can be written in the form

[tex]y=a*b^x[/tex]

where a is the initial condition and b is the growth/decay rate.  It's growth if the number is greater than 1 and it's decay if the number is less than 1 but greater than 0.  Our initial conditions are, in coordinate form where 2011 is year 0:

(0, 2.31) (2, 2.83)

Use those to find the equation for our situation.  Always start out with the coordinate that has a 0 as x, since anything raised to the power of 0 is equal to 1. So we begin with the coordinate (0, 2.31):

[tex]2.31=a*b^0[/tex] so

2.31 = a

Now we use that a value along with the x and y from the other coordinate to come up with our growth or decay rate:

[tex]2.83=2.31b^2[/tex]

Divide both sides by 2.31 to begin to isolate the b:

[tex]\frac{2.83}{2.31}=b^2[/tex] and

[tex]b^2=1.225108225[/tex] so

b = 1.106846

That means that this is a growth rate (but you knew that already).

The equation then for this particular situation is:

[tex]y=2.31(1.106846)^x[/tex]

That answers part a.

For part b, we will use that equation to find y when x = 4 (2015-2011 = 4):

[tex]y=2.31(1.106846)^4[/tex]

Raise what's inside the parenthesis to the power of 4 to get:

y = 2.31(1.500889778) so

y = 3.47 trillion

For part c. we are looking for x when y = 10:

[tex]10=2.31(1.106846)^x[/tex]

Divide both sides by 2.31 to get:

[tex]4.329004329=1.106846^x[/tex]

Take the natural log of both sides to enable us to bring the x down front:

[tex]ln(4.329004329)=xln(1.106846)[/tex]

Now divide both sides by the growth rate to get that

x = 14.434 or approximately 14 years after 2011 which is the year 2025.

Using an exponential function, we have that:

a)

The growth rate is [tex]k = 0.101515[/tex]

The function is:

[tex]F(t) = 2.31e^{0.101515t}[/tex]

b)

The estimate for the total federal receipts in 2015 is of $3.47 trillion.

c)

Federal receipts will be of $10 trillion in 2025.

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Assume that the growth of federal​ receipts, F, can be modeled by an exponential function and use 2011 as the base year:

This means that the function for the amount in t years after 2011, in trillions of dollars, is:

[tex]F(t) = F(0)e^{kt}[/tex]

In 2011 a​ country's federal receipts​ (money taken​ in) totaled ​$2.31 trillion.

Thus [tex]F(0) = 2.31[/tex].

[tex]F(t) = 2.31e^{kt}[/tex]

Item a:

In​ 2013, total federal receipts were ​$2.83 trillion, which means that [tex]F(2) = 2.83[/tex], which is used to find k.

[tex]F(t) = 2.31e^{kt}[/tex]

[tex]2.83 = 2.31e^{2k}[/tex]

[tex]e^{2k} = \frac{2.83}{2.31}[/tex]

[tex]\ln{e^{2k}} = \ln{\frac{2.83}{2.31}}[/tex]

[tex]2k = \ln{\frac{2.83}{2.31}}[/tex]

[tex]k = \frac{\ln{\frac{2.83}{2.31}}}{2}[/tex]

[tex]k = 0.101515[/tex]

The growth rate is [tex]k = 0.101515[/tex]

The function is:

[tex]F(t) = 2.31e^{0.101515t}[/tex]

Item b:

2015 is 4 years after 2011, thus this is F(4).

[tex]F(4) = 2.31e^{0.101515(4)} = 3.47[/tex]

The estimate for the total federal receipts in 2015 is of $3.47 trillion.

Item c:

This is t years after 2011, considering t for which F(t) = 10. Thus:

[tex]F(t) = 2.31e^{0.101515t}[/tex]

[tex]10 = 2.31e^{0.101515t}[/tex]

[tex]e^{0.101515t} = \frac{10}{2.31}[/tex]

[tex]\ln{e^{0.101515t}} = \ln{\frac{10}{2.31}}[/tex]

[tex]0.101515t = \ln{\frac{10}{2.31}}[/tex]

[tex]t = \frac{ \ln{\frac{10}{2.31}}}{0.101515}[/tex]

[tex]t = 14.4[/tex]

2011 + 14 = 2025.

Federal receipts will be of $10 trillion in 2025.

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