Answer:
188.31g of ZnCl2
Explanation:
First, we need to write a balanced equation for the reaction between Zn and HCl. This is shown below:
Zn + 2HCl —> ZnCl2 + H2
Molar Mass of Zn = 65g/mol
Molar Mass of ZnCl2 = 65 + (2x35.5) = 65 + 71 = 136g/mol
From the equation,
65g of Zn produced 136g of ZnCl2.
Therefore, 90g of Zn will produce = (90 x 136)/65 = 188.31g of ZnCl2
