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There are 4 red balls and 6 black balls in a bag. Draw consecutively 3 balls with replacement. Find the probability when the first two balls drawn are black and the third ball drawn is red.​

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Answer:

[tex]\frac{1}{3} *\frac{1}{2} =\frac{1}{6}[/tex]

Step-by-step explanation:

So the first two balls are black, so the way to change the path is to take two out of six black balls over two out of ten balls, which is 1/3.

If the last one is red then the probability is that if you take one of the four red balls and you take one of the eight balls, you get 1/2.

So the total probability is 1/3 times 1/2 is 1/6.

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