Answer:
[tex]x=9m[/tex]
Explanation:
According to Newton's second law, we have:
[tex]-F_f=ma(1)[/tex]
The force of friction is opposite to the motion of the block.
Using the following kinematic equation, we can calculate the distance traveled by the block before it stops([tex]v_f=0[/tex]).
[tex]v_f^2=v_0^2+2ax[/tex]
Solving for x and replacing a from (1):
[tex]x=\frac{v_f^2-v_0^2}{2a}\\x=\frac{0-v_0^2}{2(\frac{-F_f}{m})}\\x=\frac{mv_0^2}{2F_f}\\x=\frac{10kg(6\frac{m}{s})^2}{2(20N)}\\x=9m[/tex]
