Answer:
Step-by-step explanation:
Let (x), (x+1), and (x+2) be the three consecutive integers.
Put the words into expressions
Sum of the 3rd and twice the 3rd: (x)+2(x+2)
93 more than the second integer: 93+(x+1)
Now you can set up the equation and solve:
(x)+2(x+2)=93+(x+1)
Distribute and combine like terms
x+2x+4=94+x
3x+4=94+x
2x=90
x=45
So the 3 consecutive integers are 45, 46, 47.
Plug back in to check.
