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An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s as it left the bow. During this acceleration, what was the net force on the arrow to the nearest newton?

Respuesta :

skyluke89

Answer:

300 N

Explanation:

The net force acting on the arrow is given by Newton's Second Law:

[tex]F=ma[/tex]

where

m = 0.06 kg is the mass of the arrow

a = 5,000 m/s^2 is the acceleration of the arrow

Substituting the numbers into the equation, we find

[tex]F=(0.06 kg)(5,000 m/s^2)=300 N[/tex]

Answer:

300 N

Explanation:

because it is

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