Answer:
It is a double replacement reaction, and all four compounds are different.
Step-by-step explanation:
The equation for the reaction is
[tex]\underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{reactants}} \longrightarrow \underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{products}}[/tex]
This must be a double replacement reaction, in which the metal cations trade partners and all four compounds are different.
(A) and (C) are wrong, because single replacements involve elements in reactions of the type
element + compound ⟶ element + compound
(D) is wrong because, if each compound retained the same set of ions, there would be no reaction.
Answer:
It is a double replacement reaction, and all four compounds are different.
Explanation:
Just took the FLVS 4.03 Single and Double Replacement Reactions quiz. I got a 100.
