PLEASE HELP QUICK !!!!!!!!!!!
The table below shows the number of marbles of different colors in a box. A fair coin is shown below the table.
red : 10
Blue : 1
Green : 5
pink : 4
Dan selects a marble from the box randomly without looking and then tosses the fair coin. What is the probability that Dan will select a blue marble and the coin will land tails up?

a : 1 / 40
b: 3 / 40
c : 11 / 20
d : 19 / 20

Respuesta :

Total number of marbles = 10 + 1 + 5 + 4 = 20
Number of blue marbles = 1

The probability of selecting a blue marble = Number of blue marbles / Total number of marbles

So,

Probability of selecting a blue marble = [tex] \frac{1}{20} [/tex]

Number of outcomes of tossing a coin = 2
Number of favorable outcomes = 1 (Landing tail up)

So,

Probability of landing tail up = 1/2

Since, the two events are independent, the probability of occurring of both together will be the product of probabilities of individual events, so we can write:

Probability that Dan will select a blue marble and the coin will land tails up = 1/20 x 1/2 = 1/40

So, the answer to this question is option A

Answer:

1/40 (A)

Step-by-step explanation: