14KMnO4 + 4C3H5(OH)3 7K2CO3 + 7Mn2O3 + 5CO2 + 16H2O How many moles of KMnO4 are consumed to form 0.886 moles of carbon dioxide?

Respuesta :

The balanced equation is given as;
14KMnO
 + 4CH(OH) → 7KCO + 7MnO + 5CO + 16HO
      14                           :                                             5

The formed moles of CO
₂ = 0.886 mol

The stoichiometric ratio between CO₂ and KMnO₄ is 5 : 14

Hence,
 moles of CO₂ / moles of KMnO₄ = 5 / 14
  0.886 mol     / moles of KMnO₄ = 5 / 14
                        moles of KMnO₄  = 0.886 mol x 14 / 5
                        moles of KMnO₄  = 2.4808 mol

hence, consumed KMnO₄  moles = 2.4808 mol 

Answer:

2.4808 mol

Explanation:

edge 2020