Answer:
The solutions are [tex]-2+ 2\sqrt{6}\texttt{ and}-2- 2\sqrt{6}[/tex]
Step-by-step explanation:
We have to find solution of x²+4x+10.
Solution is given by
[tex]\frac{-4\pm \sqrt{4^2-4\times 1\times 10}}{2\times 1}=\frac{-4\pm \sqrt{16-40}}{2}=-2\pm 2\sqrt{6}[/tex]
So the solutions are [tex]-2+ 2\sqrt{6}\texttt{ and}-2- 2\sqrt{6}[/tex]
