Answer:
Equivalent resistance of this circuit is 1.6 ohms.
Explanation:
In the given figure, the three resistors are connected in parallel with 12 Volt battery. In parallel combination of resistors, the potential difference across each resistor is same but the current across each resistors divides.
The equivalent resistance is given by :
[tex]\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}[/tex]
Here, R₁ = 3 ohms, R₂ = 6 ohms and R₃ = 9 ohms
[tex]\dfrac{1}{R_p}=\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{9}[/tex]
[tex]R_p=1.6\ \Omega[/tex]
Hence, the equivalent resistance of this circuit is 1.6 ohms.
