Bill left burlington, vermont, and traveled to ottawa, ontario, the capital of canada. the distance from burlington to the canadian border is approximately 42 miles. the distance from the canadian border to ottawa is approximately 280 kilometers. if it took him 4.3 hours to complete the trip, what was his average speed in miles per hour?

Respuesta :

Answer is 9.7 because you need to take42÷4.3,i think so

The average speed of Bill in his considered trip was 50.23 miles per hour approximately.

How is average speed calculated?

The average speed is the ratio of total length traveled to total time taken to travel that length.

Thus, if

[tex]d_2 = \text{final position}\\d_1 = \text{initial position}\\t_2 = \text{end time}\\t_1 = \text{start time (of travelling)}then, S_a = \dfrac{d_2 - d_1}{t_2 - t_1}[/tex]

where [tex]S_a[/tex] average speed of the traveler.

For the considered case, Bill traveled from Burlington to Canadian border(42 miles) and then from Canadian border to Ottawa (280 km).

The time for travel = 4.3 hours (the difference between initial time and final time)

The total distance traveled = 42 miles + 280 km

We need average speed in miles, so converting km to miles:

1 km = 0.62137 miles approx.

280 km = 173.98 miles approx

Thus, total distance traveled by Bill = 42 + 173.98 = 215.98 miles approx.

Thus, the average speed of Bill during this trip was:

[tex]S_a =\dfrac{\text{Total distance traveled}}{\text{Total time taken}}\approx \dfrac{215.98}{4.3} \approx 50.23 \: \rm miles/hour[/tex]

Thus, the average speed of Bill in his considered trip was 50.23 miles per hour approximately.

Learn more about average speed here:

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