The molarity of HCl prepared by diluting 200.0 ml of 0.5 M HCl to a total volume of 1.00 L is calculated using the following formula
M1V1=M2V2
M1= 200 ml
V1= 0.5 M
M2=?
V2= 1.00 L = 1x 1000 = 1000ml
M2 is therefore = M1V1/V2
that is 0.5M x 200 ml/1000 Ml = 0.1 M
