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Mr. Jones places money into two separate investment accounts.
The function f(x) = 2,500(1.078)x models the value of account 1 after x years.
The table represents the value of account 2 after x years.
Number of Years, x 0 3 4 6
Value, y $2,500 $3,400 $3,700 $4,300
During what year does the value of account 1 exceed the value of account 2?

Respuesta :

aroshiayub
account 1 : y = 2500(1.078)x
account 2 : y = 2500 + 300x

after the second year a1 exceeds a2

after 2 years, a1 = 5390
after 2 years , a2 = 3100

Mr. Jones place money into two seperate investment accounts The value of account 1 exceed the value of account 2 in TWO years

The Funtion f(x)=2,500(1.078)x

Given that investment in two accounts as :-

                        Number of Years: x 0 3 4 6

                        Value y: $2,500 $3,400 $3,700 $4,300

The value of account 1 after x years will be:-

Account 1 : y = 2500(1.078)x

The value of account 2 after x years will be :-

Account 2 : y = 2500 + 300

Affter Second year account 1 exceeds account 2.

The amount will be after 2 years in Account 1 = 5390

The amount will be after 2 years in Account 2= 3100

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