Answer:- 2.39 mL are required.
Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:
[tex]M_1V_1=M_2V_2[/tex]
Where, [tex]M_1[/tex] and [tex]M_2[/tex] are molarities of concentrated and diluted solutions and [tex]V_1[/tex] and [tex]V_2[/tex] are their respective volumes.
[tex]M_1[/tex] = 1.10M
[tex]M_2[/tex] = 5.00mM = 0.005M (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)
[tex]V_1[/tex] = ?
[tex]V_2[/tex] = 525 mL
Let's plug in the given values in the formula:
[tex]1.10M(V_1)=0.005M(525mL)[/tex]
[tex]V_1=(\frac{0.005M*525mL}{1.10M})[/tex]
[tex]V_1=2.39mL[/tex]
So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.