Answer:
A) 2.7 × 102 joules
Explanation:
The work done by a constant force is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the distance over which the force is applied
[tex]\theta[/tex] is the angle between the direction of the force and the displacement
In this problem, we have:
[tex]F=0.1 \cdot 10^2 N[/tex]
d=30 m
[tex]\theta=25^{\circ}[/tex]
Substituting into the equation, we find the work done
[tex]W=Fd cos \theta=(0.1 \cdot 10^2 N)(30 m)(cos 25^{\circ})=271 J=2.7 \cdot 10^2 J[/tex]
