We have the following equation:
2x2-3x + 1
Using resolver we have:
x = (- b +/- root (b2-4ac)) / (2a)
Substituting values we have:
x = (- (- 3) +/- root ((- 3) 2-4 (2) (1))) / (2 (2))
Rewriting:
x = (3 +/- root (9-8)) / (4)
x = (3 +/- root (1)) / (4)
b2-4ac = 1> 0
root(b2-4ac) = 1 < 3
Answer:
Two positive real solutions
option C
