We know that ?T b = Kbx m
Where
?T b= elevation in boiling point
= boiling point of solution - boilinging point of pure solvent
= 81.84 - 80.1
= 1.74 °C
Kb = elevation in boiling point constant of benzene= 2.65 °C/m
m = molality of the solution
= ( mass / Molar mass ) / weight of the solvent in Kg
= (1.595 g/ M) / 0.015 kg
= 106.3/M
Plug the values we get M = 162 g/ mol
empirical formula is CH₂ it's mass is 12+2=14
N= molarmass/ empirical mass
N= 162/14
N~12
So molecular formula is 14(CH₂)= C₁₄H₂₈
