Respuesta :

mathstudent55
[tex] f(x) = x^2 - 36 [/tex]

[tex] y = x^2 - 36 [/tex]

[tex] x = y^2 - 36 [/tex]

[tex] y^2 = x + 36 [/tex]

[tex] y = \pm \sqrt{x + 36} [/tex]

[tex] f^{-1}(x) = \pm \sqrt{x + 36} [/tex]

The answer is f−1(x)=√36+x,−√36+x

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