Drew burned 2,000 calories Friday playing one hour of basketball and canoeing for two hours. Saturday he spent two hours playing basketball in 3 hours canoeing and burned 3,300 calories. how many calories did he burn per hour when playing basketball? how many calories did he burn per hour when canoeing?

To answer this, write a system of equations and use one to solve the other.

b + 2c = 2000 or b = 2000 - 2c (substitute this in for b in the 2nd equation)

2b + 3c = 3300
2 (2000 - 2c) + 3c = 3300
4000 - 4c + 3c = 3300
4000 -c = 3300
-c = -700
c = 700 calories

He burned 700 calories per hour canoeing and 600 calories per hour playing basketball (2000 - 2 x 700).

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facundo3141592 facundo3141592 · Answer 2 · 2021-10-21T11:16:26+02:00

We want to find how many calories Drew burns per hour in each sport.

He burns 600 calories per hour in basketball and 700 calories per hour in canoeing.

First, we know that in one hour of basketball and 2 of canoeing, he burned 2,000 calories.

If we define B as the amount of calories he burns per hour playing basketball and C as the amount of calories he burns per hour in canoeing, we can write:

1h*B + 2h*C = 2,000 cal.

And for Saturday we can write:

2h*B + 3h*C = 3,300 cal.

Then we got a system of equations:

1h*B + 2h*C = 2,000 cal.

2h*B + 3h*C = 3,300 cal.

Removing all the hours by dividing both equations by one hour, we get:

B + 2*C = 2,000 cal/h

2*B + 3*C = 3,300 cal/h

To solve this, first we need to isolate one variable in one equation, let's isolate B in the first one.

B = 2,000 cal/h - 2*C

Now we can replace it in the other equation:

2*(2,000 cal/h - 2*C) + 3*C = 3,300 cal/h

4,000 cal/h - C = 3,300 cal/h

C = 4,000 cal/h - 3,300 cal/h = 700 cal/h

Now that we know the value of C, we can solve:

B = 2,000 cal/h - 2*C = 2,000 cal/h - 2*700 cal/h = 600 cal/h

So he burns 600 calories per hour in basketball and 700 calories per hour in canoeing.

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