Respuesta :
Question:
Consider the graph of function f.
[tex]f\left(x\right)=\sqrt{x-4}-1[/tex]
( graph in photo below )
What is the domain of function f?
Answer:
[tex]\left(4,\ \infty\right)[/tex]
Explanation:
( In photo below )



The domain will be [tex](-2, 2) \bigcup (3, \infty )[/tex]
Function
It shows the relationship between variables.
Given
[tex]\rm f(x) = \sqrt{\dfrac{x^{2}-4 }{x-3} }[/tex]
How to get the domain?
At -2 < x < 2 It is defined
At x=2, the numerator becomes zero. But the denominator becomes negative so the function becomes imaginary.
At x=3, the denominator becomes zero that is not defined.
so, the domain will be [tex](-2, 2) \bigcup (3, \infty )[/tex].
More about the function link is given below.
https://brainly.com/question/5245372