Total possible outcomes = 36
Total possible outcomes with sum equal to 4 = 3
{1, 3} {2, 2}, (3, 1}
P(sum equal to 4) = 3/36 = 1/12
If you throw it 1000 times,
Number of times expected to have a sum of 4 = 1/12 x 1000 = 83 times
Answer: About 83 times
